Question

Prove the following formulae to the given latters:
$C=\frac{5}{9}(F-32),F$

Answer 1

$C=\frac{5}{9}(F-32)$

$9C=5F-160$

$(9C+160)=5F$

$F=\left(\frac{9C+160}{5}\right)$

$F=\frac{9}{5}C+32$