Prove the following:
sin 5x + sin 3xcos 5x + cos 3x=tan 4x
We have
L.H.S. = sin 5x + sin 3xcos 5x + cos 3x
= 2 sin(5x+3x2) cos(5x−3x2)2 cos(5x+3x2)cos(5x−3x2)
⎡⎢⎣∵sin C+sin D=2sin(C+D2)cos(C−D2)cos C + cos D=2cos(C+D2)cos(C−D2)⎤⎥⎦
= 2 sin 4x cos x2 cos 4x cos x=tan 4x
= R.H.S.