CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Prove the following identity.
sinA+cosAsinAcosA+sinAcosAsinA+cosA=22sin2A1.

Open in App
Solution

sinA+cosAsinAcosA+sinAcosAsinA+cosA=22sin2A1
Take L.H.S
=sinA+cosAsinAcosA+sinAcosAsinA+cosA
=(sinA+cosA)2+(sinAcosA)2(sinAcosA)(sinA+cosA)
=sin2+cos2A+2sinAcosA+sin2+cos2A2sinAcosAsin2Acos2A
=11cosA=2(12sin2A)=22sin2A1
Hence proved

1097415_1134794_ans_9457071e80804ad5b40fcdc44a3f3288.jpg

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Trigonometric Identity- 1
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon