1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Mathematics
Basic Trigonometric Identities
Prove the fol...
Question
Prove the following identity:
sin
2
(
45
∘
+
α
)
−
sin
2
(
30
∘
−
α
)
−
sin
15
∘
cos
(
15
∘
+
2
α
)
=
sin
2
α
Open in App
Solution
sin
2
A
−
sin
2
B
=
sin
(
A
+
B
)
sin
(
A
−
B
)
=
sin
(
75
°
)
sin
(
15
+
2
α
)
−
sin
15
°
cos
(
15
+
2
α
)
=
cos
(
15
°
)
sin
(
15
+
2
α
)
−
sin
15
°
cos
(
15
+
2
α
)
=
sin
(
15
+
2
α
−
15
)
=
sin
2
α
Suggest Corrections
0
Similar questions
Q.
Identity transformations of Trigonometric Expressions.
prove the following identities.
1
−
s
i
n
2
α
1
+
s
i
n
2
α
=
c
o
t
2
(
π
4
+
α
)
.
Q.
If
3
π
4
<
α
<
π
then
√
2
cot
α
+
1
sin
2
α
is equal to
Q.
If
3
π
/
4
<
α
<
π
, then
√
2
cot
α
+
1
sin
2
α
is equal to
Q.
Prove that cos 105° + cos 15° = sin 75° − sin 15°.
Q.
Evaluate the following :
s
i
n
2
30
∘
+
s
i
n
2
45
∘
+
s
i
n
2
60
∘
+
s
i
n
2
90
∘
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Pythagorean Identities
MATHEMATICS
Watch in App
Explore more
Basic Trigonometric Identities
Standard XII Mathematics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app