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Byju's Answer
Standard XII
Mathematics
Basic Trigonometric Identities
Prove the fol...
Question
Prove the following identity:
sin
2
(
45
∘
+
α
)
−
sin
2
(
30
∘
−
α
)
−
sin
15
∘
cos
(
15
∘
+
2
α
)
=
sin
2
α
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Solution
sin
2
A
−
sin
2
B
=
sin
(
A
+
B
)
sin
(
A
−
B
)
=
sin
(
75
°
)
sin
(
15
+
2
α
)
−
sin
15
°
cos
(
15
+
2
α
)
=
cos
(
15
°
)
sin
(
15
+
2
α
)
−
sin
15
°
cos
(
15
+
2
α
)
=
sin
(
15
+
2
α
−
15
)
=
sin
2
α
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