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Question

Prove the following identity:
sin2(45+α)sin2(30α)sin15cos(15+2α)=sin2α

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Solution

sin2Asin2B=sin(A+B)sin(AB)
=sin(75°)sin(15+2α)sin15°cos(15+2α)
=cos(15°)sin(15+2α)sin15°cos(15+2α)
=sin(15+2α15)
=sin2α

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