Proving LHS = RHS.
First we consider Left Hand Side (LHS),
1cosA+sinA–1+1cosA+sinA+1
By taking LCM we get,
=(cosA+sinA+1+cosA+sinA–1)(cosA+sinA)2–12
We know that, (a+b)2=a2+2ab+b2
=2(cosA+ sinA)cos2A+sin2A+2cosAsinA–1
=2(cosA+sinA)2cosAsinA
=cosA+sinAcosAsinA
=cosAcosAsinA+sinAcosAsinA
=cosecA+ secA.
Then, Right Hand Side=cosecA+secA.
Therefore, LHS = RHS.
Hence proved.