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Byju's Answer
Standard XII
Mathematics
Properties of Determinants
Prove the fol...
Question
Prove the following :
∣
∣ ∣
∣
y
+
z
z
y
z
z
+
x
x
y
x
x
+
y
∣
∣ ∣
∣
=
4
x
y
z
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Solution
Apply
C
1
−
(
C
2
+
C
3
)
to make one zero we get
△
=
∣
∣ ∣
∣
0
z
y
−
2
x
z
+
x
x
−
2
x
x
x
+
y
∣
∣ ∣
∣
Take out
−
2
x
from
C
1
and then apply
R
2
−
R
3
Δ
=
−
2
x
∣
∣ ∣
∣
0
z
y
0
z
−
y
1
x
x
+
y
∣
∣ ∣
∣
=
−
2
x
(
−
z
y
−
z
y
)
=
4
x
y
z
.
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Q.
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Q.
If
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Prove that:
∣
∣ ∣
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Q.
Shows that
∣
∣ ∣
∣
y
+
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x
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y
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+
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