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Question

Prove the following :
∣ ∣y+zzyzz+xxyxx+y∣ ∣=4xyz

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Solution

Apply C1(C2+C3) to make one zero we get
=∣ ∣0zy2xz+xx2xxx+y∣ ∣
Take out 2x from C1 and then apply R2R3
Δ=2x∣ ∣0zy0zy1xx+y∣ ∣
=2x(zyzy)=4xyz.

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