CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Prove the following:
(xaxb)a2+ab+b2×(xbxc)b2+bc+c2×(xcxa)c2+ca+a2=1

Open in App
Solution

(xaxb)a2+ab+b2×(xbxc)b2+bc+c2×(xcxa)c2+a2+ca=x(ab)(a2+b2+ab)×x(bc)(b2+bc+c2)×x(ca)(c2+a2+ca)=x(a3b3)×x(b3c3)×x(c3a3)=xa3b3+b3c3+c3a3=x=1

flag
Suggest Corrections
thumbs-up
8
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Laws of Indices
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon