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Question

Prove the following statements.
(sinA+cosA)(1sinAcosA)=sin3A+cos3A.

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Solution

LHS:
(sinA+cosA)(1sinAcosA)
sinA+cosAsin2AcosAsinAcos2A (1)
Substitute sin2A=1cos2A
cos2A=1sin2A
sinA+cosAsin2AcosAsinAcos2A
sinA+cosA(1cos2A)cosAsinA(1sin2A)
sinA+cosA(1cos2A)cosAsinA(1sin2A)
sinA+cosAcosA+cos3AsinA+sin3A
cos3A+sin3A
LHS=RHS
Hence proved.

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