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Question

Prove the following :
tan(π4+θ)=1+tanθ1tanθ

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Solution

we know tan(a+b)=tan(a)+tan(b)1tan(a).tan(b)

given tan(π4+θ)=tanπ4+tanθ1tanπ4×tanθ=1+tanθ1tanθ[tanπ4=1][using above formula]

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