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Question

Prove the following trignometric identities:

tan θ+1tan θ=sec θ cosec θ

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Solution

We know that,

(sec2θtan2θ)=1

So,

tanθ+1tanθ=tan2θ+1 tanθ =sec2θtanθ =secθsecθtanθ =secθ1cosθsinθcosθ =secθ1sinθ

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