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Question

Prove the following trigonometric identities:

11+sin A+11sin A=2 sec2 A

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Solution

LHS = 11+sinA11+sinA + 11sinA11sinA

We know that cos2θ+sin2θ=1

sec θ=1cos θ

LHS=11+sin A+11sin A

=1+sin A+1sin A(1+sin A)(1sin A)

=21sin2 A

=2cos2 A

=2sec2 A=RHS


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