Prove the following trigonometric identities-i A -tan B B -tan A - A tan Bii tan A -tan B A - B -tan A tan B

(i) We have to prove Now, nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Complementary Trigonometric Ratios

Prove the fol...

Question

Prove the following trigonometric identities.

(i) $\frac{\cot A + \tan B}{\cot B + \tan A} = \cot A \tan B$

(ii) $\frac{\tan A + \tan B}{\cot A + \cot B} = \tan A \tan B$

Open in App

Solution

Suggest Corrections

Similar questions

\frac{\tan A + \tan B}{\cot A + \cot B} = \tan A \tan B

\frac{\tan A + \tan B}{\cot A + \cot B} = \tan A \tan B

\frac{\cos A cosec A - \sin A \sec A}{\cos A + \sin A} = cosec A - \sec A

\frac{\sin A}{\sec A + \tan A - 1} + \frac{\cos A}{cosec A + \cot A - 1} = 1

Prove the following trigonometric identities:

$\frac{s e c A - t a n A}{s e c A + t a n A} = \frac{c o s^{2} A}{(1 + s i n A)^{2}}$

\cot θ - \tan θ = \frac{2 \cos^{2} θ - 1}{\sin θ \cos θ}

\tan θ - \cot θ = \frac{2 \sin^{2} θ - 1}{\sin θ \cos θ}

\frac{\sin A - 2 \sin^{3} A}{2 \cos^{3} A - \cos A} = \tan A

Join BYJU'S Learning Program