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Question

Prove the following trigonometric identities.

(i) sec θ-1sec θ+1+sec θ+1sec θ-1=2 cosec θ
(ii) 1+sin θ1-sin θ+1-sin θ1+sin θ=2 sec θ
(iii) 1+cos θ1-cos θ+1-cos θ1+cos θ=2 cosec θ
(iv) sec θ-1sec θ+1=sin θ1+cos θ2
(v) sinθ+1-cosθcosθ-1+sinθ=1+sinθcosθ

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Solution

(i) We have,

(ii) We have,

(iii) We have,

(iv) We have,

Multiplying both the numerator and the denominator by, we have

(v) We have,

Multiplying both the numerator and the denominator by , we have


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