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Question

Prove the following trigonometric identities:

(i) 1+sin A1sin A=sec A+tan A

(ii) 1cos A1+cos A+1+cos A1cos A=2 cosec A

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Solution

(i) 1+sin A1sin A=sec A+tan A

LHS=1+sin A1sin A

Rationalize the numerator and denominator with 1+sin A

LHS=(1+sin A)(1+sin A)(1sin A)(1+sin A)

=(1+sin A)21sin2A


=(1+sin A)2cos2A

=1+sin AcosA

=1cosA+sin AcosA

=sec A+tan A

=RHS

(ii) 1cos A1+cos A+1+cos A1cos A=2 cosec A


LHS=1cos A1+cos A+1+cos A1cos A

Rationalize the numerator and denominator,

=(1cos A)(1cos A)(1+cos A)(1cos A)+(1+cos A)(1+cos A)(1cos A)(1+cos A)

=(1cos A)21cos2A+(1+cos A)21cos2A

=(1cos A)2sin2A+(1+cos A)2sin2A

=(1cos A)sinA+(1+cos A)sinA

=1sinAcos AsinA+1sinA+cos AsinA

=cosecAtanA+cosecA+tanA

=2 cosec A

=RHS


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