Prove the identity - tan- - 2 - tan- - 2 -4

( tanθ #160; +θ #160; #160; ) #160; ^ 2 ( tanθ #160; θ #160; #160; ) #160; ^ 2 =4 ⇒ L.H.S=( tanθ #160; +θ #160; #160; ) ...

You visited us 2 times! Enjoying our articles? Unlock Full Access!

Domain and Range of Trigonometric Ratios

Prove the ide...

Question

Prove the identity :
${(tan θ + cot θ)}^{2} - {(tan θ - cot θ)}^{2} = 4$

Open in App

Solution

Suggest Corrections

Similar questions

{(tan θ + sec θ)}^{2} + {(tan θ - sec θ)}^{2} = \frac{2 (1 + {sin}^{2} θ)}{{cos}^{2} θ}

Prove that $(t a n θ + c o t θ)^{2} =$ _____________

\frac{c o t A + t a n B}{c o t B + t a n A} = c o t A t a n B

\frac{1 + t a n^{2} θ}{1 + c o t^{2} θ} = {(\frac{1 - t a n θ}{1 - c o t θ})}^{2}

(tan θ + cot θ)^{2} = {sec}^{2} θ + c o s e c^{2} θ

Prove the following trigonometric identities:

$\frac{1 + t a n^{2} θ}{1 + c o t^{2} θ} = {(\frac{1 - t a n θ}{1 - c o t θ})}^{2} = t a n^{2} θ$

Join BYJU'S Learning Program