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Question

Prove the root of equation ax2+bx+c=0 is x=b±b24ac2a

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Solution

Consider the quadratic equation ax2+bx+c
a(x2+bax+ca)=0

x2+bax+ca=0

x2+bax=ca

This can be written as
x2+2×b2ax=ca

Add (b2a)2 on both sides

x2+2×(b2a)x+(b2a)2=ca+(b2a)2

This can be written as

(x+b2a)2=ca+b24a

(x+b2a)2=4ac+b24a2

x+b2a=±4ac+b24a2

x+b2a=±b24ac2a

x=b2a±b24ac2a

x=b±b24ac2a

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