Prove v = u + at
where u = initial velocity, v = final velocity, a = acceleration and t = time period

Open in App

Solution

We know acceleration (a) = rate of change of velocity

= $\frac{c h a n g e i n v e l o c i t y}{t i m e i n t e r v a l}$

= $\frac{f i n a l v e l o c i t y - i n i t i a l v e l o c i t y}{t i m e p e r i o d}$

= $\frac{v - u}{t}$

$∴ a = \frac{v - u}{t} o r a \times t = v - u$
or at = v - u or at + u = v
$∴$ v = u + at

Suggest Corrections

Similar questions

Write three equations of uniformly accelerated motion relating the initial velocity (u),final velocity (v), time(t), acceleration (a) and displacement (S).

Q. Assertion :Displacement-time graph is a parabola corresponding to straight line parallel to X-axis, on a velocity-time graph. Reason: If

v = u + a t

, then

s = u t + \frac{1}{2} a t^{2}

, where

v

u

are final and initial velocities and

a

is acceleration,

t

is time and

s

is displacement traveled in time

t

The initial velocity of a particle is u (at t=0) and the acceleration f is given by $f = a t$ where $a$ is a constant. Which of the following relation is valid?