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Byju's Answer
Standard XII
Mathematics
Circular Measurement of Angle
Prove with th...
Question
Prove with the help of trigonometric Identities.
2
s
i
n
2
θ
+
4
s
e
c
2
θ
+
5
c
o
t
2
θ
+
2
c
o
s
2
θ
−
4
t
a
n
2
θ
−
5
c
o
s
e
c
2
θ
=
1
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Solution
L.H.S.
=
2
s
i
n
2
θ
+
4
s
e
c
2
θ
+
5
c
o
t
2
θ
+
2
c
o
s
2
θ
−
4
t
a
n
2
θ
−
5
c
o
s
e
c
2
θ
=
2
s
i
n
2
θ
+
2
c
o
s
2
θ
+
4
s
e
c
2
θ
−
4
t
a
n
2
θ
+
5
c
o
t
2
θ
−
5
c
o
s
e
c
2
θ
=
2
(
s
i
n
2
θ
+
c
o
s
2
θ
)
+
4
(
1
+
t
a
n
2
θ
)
−
4
t
a
n
2
θ
+
5
c
o
t
2
θ
−
5
(
1
+
c
o
t
2
θ
)
=
2
+
4
−
5
=
1
=
R
.
H
.
S
.
Hence,
2
s
i
n
2
θ
+
4
s
e
c
2
θ
+
5
c
o
t
2
θ
+
2
c
o
s
2
θ
−
4
t
a
n
2
θ
−
5
c
o
s
e
c
2
θ
=
1
is proved.
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Similar questions
Q.
Using trigonometric identities
5
cosec
2
θ
−
5
cot
2
θ
−
3
expressed as an integer is
Q.
Prove the following trigonometric identities.
(i)
cot
θ
-
tan
θ
=
2
cos
2
θ
-
1
sin
θ
cos
θ
(ii)
tan
θ
-
cot
θ
=
2
sin
2
θ
-
1
sin
θ
cos
θ