Question

Provide reagents for the following transformation.

Answer 1

The reagents are as given below.
A: Lindlar's catalyst or$Na/N{H}_3\left(l\right)$ selectively reduces carbon carbon triple bond to carbon carbon double bond.
B: HBr(excess) adds two molecules to the carbon carbon triple bond. Bromine is added to carbon atom carrying maximum
substituents.
C:HBr (peroxide) adds a molecule of HBr to carbon carbon triple bond according to Anti Markovnikov's Rule.Bromine is
added to the carbon atom having least substituents.
D: Lindlar's catalyst then $HBr\left(ROOR\right)$. Lindlars catalyst selectively reduces triple bond to double bond. Then a molecule
of HBr is added according to Anti Markovnikov's Rule as peroxide is present..
E: $B_2{H}_6-H_2{O}_2/NaOH$ adds a molecule of water followed by keto enol tautomerism. This is hydroboration
oxidation reaction.
F: $H_{2}S{O}_4\left(aq\right)/HgS{O}_4$ adds a molecule of water followed by keto enol tautomerism. This is hydration
reaction.
G: Lindlar's catalyst then HBr. Lindlars catalyst selectively reduces triple bond to double bond. Then a molecule of HBr is
added according to Markovnikov's Rule.