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Question

# PRSU is a rectangle with PQ = 6 cm, RS = 4 cm, SU = 16 cm. What is the area of the parallelogram QRTU?

A
20 cm2
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B
40 cm2
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C
60 cm2
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D
90 cm2
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Solution

## The correct option is B 40 cm2For QRTU parallelogram, RS is the perpendicular distance between the parallel sides QR and TU, which is the height of the parallelogram. Since, PRSU is a rectangle, RP = SU = 16 cm [ Opposite sides of a rectangle are equal] QR = RP - PQ = 16 - 6 = 10 cm Now, RS = 4 cm is the height of the parallelogram and QR = 10 cm is the base of the parallelogram QRTU. Hence, area of the parallelogram QRTU = base x height = 10 cm x 4 cm = 40 cm2

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