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Hydrogen Peroxide

Prussian blue...

Question

Prussian blue has two types of iron with oxidation number as shown
$I I I F e [I I F e {(C N)}_{6}]$
net charge on Prussian blue is -x.
The value of x is..............

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Solution

According to given conditions,
$I I I F e [I I F e {(C N)}_{6}]$
$+ 3 + 2 - 6 * 1 = - 1$ so net charge on compound is $- 1$ .
So value of x is 1.

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