PS II accepts electrons from

O H^{-}

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O^{2 -}

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H^{+}

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Both A and C

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Solution

The correct option is A $O H^{-}$
Water is split in chloroplasts in the light reaction of photosynthesis. Chlorophyll, acting as a photopigment, captures sunlight and transfers that energy to an electron pair of a water molecule. Water molecule is separated into 2 protons, molecular oxygen and a free electron pair, which then enters to PS II and accepted by plastoquinone and carried by variety of electron acceptors in a series of redox potential. The excited electrons are used for photolysis of water generating oxygen and protons which then used in synthesis of ATP and NADPH.

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Similar questions

Q. Electrons from excited chlorophyll of PS II are accepted first by

Splitting of water molecules during light reaction of photosynthesis is associated with

(a) PS I resulting in the release of $O_{2}$ , protons and transfer of electrons to PS II

(b) PS II resulting in release of $O_{2}$ , protons and transfer of electrons to PS I

(d) PS I resulting in the release of $O_{2}$ , protons and transfer of electrons to PS I.

Of the above statements

Q. Assertion :The splitting of water is associated with ps II. Reason: Water is split into

H^{+}

O_{2}

and electrons.

Q. Assertion :The splitting of water is associated with PS II Reason: Water is split into

H^{+}, O_{2}

and electrons

Question 11
The correct sequence of flow of electrons in the light reaction is
(a) PS II, plastoquinone, cytochromes, PS I ferredoxin
(b) PS I, plastoquinone, cytochromes, PS II, ferredoxin
(c) PS I, ferredoxin, PS II
(d) PS I, plastoquinone, cytochromes, PS II, ferredoxin

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