Let us look at the two triangles
(
△PQS and
△PRS) inside
△PQR.
Side
PS is common to both the triangles.
−−−(1)
Also,
PS is an angle bisector.
⟹∠QPS=∠RPS−−−(2)
PQ=PR−−−(3) (Given)
⟹△PQS≅△PRS
(by the Side-Angle-Side criterion of congruence)
We know that corresponding parts of the congruent triangles are equal.
⟹QS=RS
∴RS=5 ft
⟹QR=QS+RS=5 ft+5 ft =10 ft