Pt H 2- H - pH -2- H - pH -3 - Pt H 21 atm 1 atmThe cell reaction for the given cell is-A- spontaneousB- non-spontaneousC- at equilibriumD- None of these

The correct option is B non spontaneousE_cell=E^0_cell 0.0591/n log_10[H^+]_anode[H^+]_cathode nbsp; This is a special type of cell in which we have E^0 =0 ...

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Byju's Answer

Standard XII

Chemistry

Representation of Cell

Pt H 2| H + p...

Question

$P t (H_{2}) | H^{+} (p H = 2) | H^{+} (p H = 3) | P t (H_{2})$
1 atm 1 atm
The cell reaction for the given cell is:

spontaneous

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non-spontaneous

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at equilibrium

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None of these

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Solution

The correct option is B non-spontaneous
$E_{c e l l} = E_{c e l l}^{0} - \frac{0.0591}{n} {log}_{10} \frac{[H^{+}]_{a n o d e}}{[H^{+}]_{c a t h o d e}}$

This is a special type of cell in which we have $E^{0} = 0$ because same type of species/ions are present in cathode and anode. It is called a concentration cell.
$= - \frac{0.0591}{1} {log}_{10} \frac{10^{- 2}}{10^{- 3}} = - 0.0591$
$= - ve$
Since $E_{c e l l}$ is negative, reaction is non-spontaneous as $△ G i s + v e$

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Similar questions

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Pt (H2) | H+(pH=2) | H+(pH=3) | Pt (H2) 1 atm 1 atm The cell reaction for the given cell is:

$P t (H_{2}) | H^{+} (p H = 2) | H^{+} (p H = 3) | P t (H_{2})$
1 atm 1 atm
The cell reaction for the given cell is: