$[P t (N H_{3}) (N H_{2} O H) (P y) (N O_{2})] N O_{3}$ has square planer shape.

How many geometrical isomers are formed?

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Solution

The correct option is B 3

$[P t (N H_{3}) (N H_{2} O H) (P y) (N O_{2})] N O_{3}$ has square planar shape and has three geometrical isomers.

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Similar questions

[P t (N H_{3}) (N H_{2} O H) (p y) (N O_{2})] N O_{3}

[C o (N H_{3})_{2} C l_{4}]^{-}

[A u C l_{2} B r_{2}]

{[P t ({N H}_{3}) ({N H}_{2} O H) P y (C l)]}^{+}

[C O (N H_{3})_{2} C l_{4}]

[A u C l_{2} B r_{2}]^{-}

[C o C l_{2} B r_{2}]^{2 -}

[M a_{2} b_{2} c_{2}]

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