Pts - Sn2- aq- 1 M- Sn4- aq- 1 M - Fe2- aq- 1 M- Fe3- aq- 1 M - PtsAnode reaction is-

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Balancing Redox Reaction

Pts | Sn2+ aq...

Question

Pt(s) | Sn²⁺ (aq, 1 M), Sn⁴⁺ (aq, 1 M) || Fe²⁺ (aq, 1 M), Fe³⁺ (aq, 1 M) | Pt(s)
Anode reaction is:

Fe²⁺ → Fe³⁺ + 1e^–

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Pt → Pt²⁺ + 2e^–

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Sn²⁺ → Sn⁴⁺ + 2e^–

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Pt → Sn²⁺ + 2e^–

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Solution

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Similar questions

Pt(s) | Sn²⁺ (aq, 1 M), Sn⁴⁺ (aq, 1 M) || Fe²⁺ (aq, 1 M), Fe³⁺ (aq, 1 M) | Pt(s)
Anode reaction is:

25^{o} C .

F e^{3 +} (a q, 0.1 M), F e^{2 +} (a q, 1 M) | P t (s); E_{F e^{3 +} / F e^{2 +}}^{0} = 0.77 V

A g (s) | A g C l (s) ∣ C l^{-} (a q, 0.001 M); E_{A g C l / A g}^{0} = 0.22 V

The oxidation half reaction for following reaction is

Fe²⁺(aq) + Cr₂O₇^2-(aq) → Fe³⁺ (aq) + Cr³⁺(aq)

2 F e^{3 +} (a q) + S n^{2 +} (a q) \to 2 F e^{2 +} (a q) + A

25^{o} C

P t (s) | F e^{2 +} (a q, 0.1 M), F e^{3 +} (a q, 0.01 M); E_{F e^{3 +} / F e^{2 +}}^{0} = + 0.77 V

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