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Question

pth term of the series (31n)+(32n)+(33n)+.... will be

A
(3+Pn)
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B
(3Pn)
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C
(3+nP)
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D
(3nP)
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Solution

The correct option is B (3Pn)
Given series (31n)+(32n)+(33n)+.... (A.P.)

Therefore common difference

d = (32n)+(31n)=1n and first term a = (31n)
Now
pth term of the series = a + (p - 1)d = (31n)+(p1)(1n)=31n+1nPn=(3Pn).

Trick : This question can also be done by inspection i.e. first 1n, second 2n, third 3n, therefore, pth will be Pn. Hence the result (3 is constant).


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