Puja works in a bank and she gets a monthly salary of Rs 35000 with annual increment of Rs 1500. What would be her monthly salary in the 10th year of her employment?

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Solution

Here a = 35000 , d = 1500 and T₁₀ = ?
We know that
T_n = a + (n - 1)d
T₁₀ = 35000 + (10 - 1) × 1500
= 35000 + (9 × 1500) = (35000 + 13500) = 48,500
Hence, Puja's monthly salary in the 10^th year will be Rs. 48,500.

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Puja works in a bank and she gets a monthly salary of Rs 35000 with annual increment of Rs 1500. What would be her monthly salary in the 10th year of her employment?

Here a = 35000 , d = 1500 and T10 = ? We know that Tn = a + (n - 1)d T10 = 35000 + (10 - 1) × 1500 = 35000 + (9 × 1500) = (35000 + 13500) = 48,500 Hence, Puja's monthly salary in the 10th year will be Rs. 48,500.

Here a = 35000 , d = 1500 and T₁₀ = ?
We know that
T_n = a + (n - 1)d
T₁₀ = 35000 + (10 - 1) × 1500
= 35000 + (9 × 1500) = (35000 + 13500) = 48,500
Hence, Puja's monthly salary in the 10^th year will be Rs. 48,500.