Pulkit lives $\frac{93}{10} k m$ away from his school and his class mate Raghav lives $6 \frac{1}{10} k m$ away from the school . How much farter does Pulkit live than Raghav from the school if they both live along the same lane and both are on same side?

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Solution

Since both lives on the same side therefore distance $= \frac{93}{10} - 6 \frac{1}{10} = \frac{93 - 61}{10} = \frac{32}{10} = \frac{16}{5}$

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Pulkit lives 9310km away from his school and his class mate Raghav lives 6110km away from the school . How much farter does Pulkit live than Raghav from the school if they both live along the same lane and both are on same side?

Since both lives on the same side therefore distance =9310−6110=93−6110=3210=165

Pulkit lives $\frac{93}{10} k m$ away from his school and his class mate Raghav lives $6 \frac{1}{10} k m$ away from the school . How much farter does Pulkit live than Raghav from the school if they both live along the same lane and both are on same side?

Since both lives on the same side therefore distance $= \frac{93}{10} - 6 \frac{1}{10} = \frac{93 - 61}{10} = \frac{32}{10} = \frac{16}{5}$