Pumping alone at their respective constant rates- one inlet pipe fills an empty tank to 1 - 2 of capacity in 3 hours and a second inlet pipe fills the same empty tank to 2 - 3 of capacity in 6 hours- How many hours will it take both pipes- pumping simultaneously at their respective constant rates- to fill the empty tank to capacity-

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Byju's Answer

Standard VII

Mathematics

Time and Work

Pumping alone...

Question

Pumping alone at their respective constant rates, one inlet pipe fills an empty tank to $\frac{1}{2}$ of capacity in 3 hours and a second inlet pipe fills the same empty tank to $\frac{2}{3}$ of capacity in 6 hours. How many hours will it take both pipes, pumping simultaneously at their respective constant rates, to fill the empty tank to capacity?

3.25

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3.6

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4.2

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4.4

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5.5

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Solution

The correct option is B 3.6
The first pipe fills half tank in 3 hrs. So, it must take 6 hrs to fill the complete tank.
The second pipe takes 6 hrs to fill 2/3 of the tank. So it must take 9 hrs to fill the tank completely.
To fill the complete tank together they will need,
$\frac{1}{1 / 6 + 1 / 9}$ = $\frac{18}{5}$ = $3.6$ hrs.

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The correct option is B 3.6The first pipe fills half tank in 3 hrs. So, it must take 6 hrs to fill the complete tank.The second pipe takes 6 hrs to fill 2/3 of the tank. So it must take 9 hrs to fill the tank completely.To fill the complete tank together they will need,11/6+1/9 = 185 = 3.6 hrs.