Puneet has a Recurring Deposit Account in the Bank of Baroda and deposits Rs140 per month for 4 years. If he gets Rs 8,092 on maturity, find the rate of interest given by the bank.
Installment per month(P) = Rs140
Number of months(n) = 48
Let rate of interest(r)= r %p.a.
S.I.=P×n(n+1)2×12×r100
=140×48(48+1)2×12×r100
=140×23522×12×r100=Rs(137.2)r
Maturity value= Rs(140 x48)+Rs(137.20)r
Given maturity value= Rs8,092
Then Rs(140 x48)+Rs(137.20)r = Rs8,092
137.20r = Rs8,092 - Rs6,720
⇒r=1,372137.20=10