Pure benzene freeze at 5.45∘C.A solution containing 7.24 g of C2H2Cl4 in 115.3 g of benzene was observed to freeze at 3.55∘C. What is the molal freezing point constant of benzene?
A
20.8∘C/m
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B
10.4∘C/m
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C
2.04∘C/m
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D
5.08∘C/m
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Solution
The correct option is D5.08∘C/m Depression in the freezing point =ΔTf=5.45−3.55=1.9oC
Molar mass of C2H2Cl4=12×2+2×1+4×(35.5)=168 g/mol
The number of moles is the ratio of mass to molecular weight.
Number of moles of solute =7.24168=0.0431
The molality of solution is the number of moles of solute in 1000 g of water.