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Question

Pure benzene freeze at 5.45C.A solution containing 7.24 g of C2H2Cl4 in 115.3 g of benzene was observed to freeze at 3.55C. What is the molal freezing point constant of benzene?

A
20.8C/m
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B
10.4C/m
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C
2.04C/m
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D
5.08C/m
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Solution

The correct option is D 5.08C/m
Depression in the freezing point =ΔTf=5.453.55=1.9oC
Molar mass of C2H2Cl4=12×2+2×1+4×(35.5)=168 g/mol
The number of moles is the ratio of mass to molecular weight.
Number of moles of solute =7.24168=0.0431
The molality of solution is the number of moles of solute in 1000 g of water.
Molality =0.0431×1000115.3=0.374
Depression in the freezing point :

ΔTf=Kbm1.9=Kb×0.374

Kb=5.08oC/m

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