You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Van't Hoff Factor

Pure benzene ...

Question

Pure benzene freezes at ${5.3}^{o} C$ . A solution of 0.223 g of phenyl acetic acid ( $C_{6} H_{5} C H_{2} C O O H$ ) in 4.4 g of benzene ( $K_{f}$ 5.12 K kg $m o l^{- 1}$ ) freezes at ${4.47}^{o} C$ . From the observation one can conclude that:

phenyl acetic acid exists as such in benzene

No worries! We‘ve got your back. Try BYJU‘S free classes today!

phenyl acetic acid undergoes partial ionization in benzene

No worries! We‘ve got your back. Try BYJU‘S free classes today!

phenyl acetic acid undergoes complete ionization in benzene

No worries! We‘ve got your back. Try BYJU‘S free classes today!

phenyl acetic acid dimerizes in benzene

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is B phenyl acetic acid dimerizes in benzene
we have,
$Δ T_{f} = i K_{f} m$
$5.3 - 4.47 = i \times 5.12 \times \frac{0.223}{136 \times 4.4} \times 1000$
we get, $i = 0.43$
and we know that if the value of $i$ is less than 1 then the molecule is getting dimerizes.

Suggest Corrections

Similar questions

Q. The freezing point of a solution containing

0.2

g of acetic acid in

20.0

g benzene is lowered by

{0.45}^{o} C

. The degree of association of acetic acid in benzene is:

[Assume acetic acid dimerizes in benzene and

K_{f}

for benzene

= 5.12

K kg mol

^{- 1}

]

Q. Pure benzene freezes at

{5.3}^{\circ} C

. A solution of

0.223 g

of phenylacetic acid

(C_{6} H_{5} C H_{2} C O O H)

4.4 g

of benzene

(K_{f} = 5.12 {Kkg mol}^{- 1})

freezes at

{4.47}^{\circ} C

. From the observation, one can conclude that

Q. The freezing point of benzene decreases by

{0.45}^{0} C

when

0.2

g of acetic acid is added to

20

g of benzene. If acetic acid is associates to form a dimer in benzene, percentage association of acetic acid in benzene will be:
(

K_{f}

for benzene = 5.12 K kg

m o l^{- 1}

)

Q. Pure benzene freezes at

{5.3}^{\circ} C

. A solution of

0.223 g

of phenylacetic acid

(C_{6} H_{5} C H_{2} C O O H)

4.4 g

of benzene

(K_{f} = 5.12 {Kkg mol}^{- 1})

freezes at

{4.47}^{\circ} C

. From the observation, one can conclude that

Q. The freezing pint of benzene decreases by

{0.45}^{o} C

when

0.2 g

of acetic acid is added to

20 g

of benzene. If acetic acid is associates to form a dimer in benzene, find the percentage association of acetic acid in benzene.

(K_{f} f o r b e n z e n e = 5.12 k g m o l^{- 1})

Join BYJU'S Learning Program

Pure benzene freezes at 5.3oC. A solution of 0.223 g of phenyl acetic acid (C6H5CH2COOH) in 4.4 g of benzene (Kf 5.12 K kg mol−1) freezes at 4.47oC. From the observation one can conclude that:

The correct option is B phenyl acetic acid dimerizes in benzenewe have,ΔTf=iKfm5.3−4.47=i×5.12×0.223136×4.4×1000we get, i=0.43and we know that if the value of i is less than 1 then the molecule is getting dimerizes.

Pure benzene freezes at ${5.3}^{o} C$ . A solution of 0.223 g of phenyl acetic acid ( $C_{6} H_{5} C H_{2} C O O H$ ) in 4.4 g of benzene ( $K_{f}$ 5.12 K kg $m o l^{- 1}$ ) freezes at ${4.47}^{o} C$ . From the observation one can conclude that:

The correct option is B phenyl acetic acid dimerizes in benzene
we have,
$Δ T_{f} = i K_{f} m$
$5.3 - 4.47 = i \times 5.12 \times \frac{0.223}{136 \times 4.4} \times 1000$
we get, $i = 0.43$
and we know that if the value of $i$ is less than 1 then the molecule is getting dimerizes.