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Standard XII

Chemistry

Physical Properties of Carbon Family

Pure N 2 O 3 ...

Question

Pure $N_{2} O_{3}$ exists only in the solid state at low temperature. Above its melting point, it dissociates to

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Solution

The correct option is A
$N_{2} O_{3} ⇌ N_{2} O + N O_{2}$

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Similar questions

Q. When

N_{2} O_{5}

is heated at temperature T, it dissociates as

N_{2} O_{5} ⇌ N_{2} O_{3} + O_{2}, K_{e} = 2.5

. At the time

N_{2} O_{3}

also decomposes as:

N_{2} O_{3} ⇌ N_{2} O + O^{2}

. If initially

4

moles of

N_{2} O_{5}

are taken in

1

litre flask and allowed to attain equilibrium, concentration of

O_{2}

was formed to be

2.5 M

. Equilibrium concentration of

N_{2} O

is:

Q. When

N_{2} O_{5}

is heated at temp. T, it dissociates as

N_{2} O_{5} ⇌ N_{2} O_{3} + O_{2}, K_{c} = 2.5

. At the same time

N_{2} O_{3} ⇌ N_{2} O + O_{2}

. If initially 4.0 moles of

N_{2} O_{5}

are taken in 1.0 litre flask and allowed to attain equilibrium, concentration of

O_{2}

was formed to be 2.5 M. Equilibrium concentration of

N_{2} O

is:

Q. The nitrogen oxides that contain N – N bond(s) is:

Q. When

N_{2} O_{3}

is heated at temp.

T

it dissociates as

N_{2} O_{5} \to N_{2} O_{3} + O_{2}, K_{c} = 2.5

. At the same time

N_{2} O_{3}

also decomposes as :

N_{2} O_{3} \to N_{2} O + O_{2}

. If initially

4.0

moles of

N_{2} O_{3}

are taken in

1.0 l i t r e

flask and allowed to attain equilibrium, concentration of

O_{2}

was formed to be

2.5 M

. Equilibrium concentration of

N_{2} O

is__________.

Q. Anhydride of an acid is formed by dehydration and oxidation number of central atom remains unchanged.
Acid :

H_{2} N_{2} O_{2}, H N O_{2}, H N O_{3}

Anhydride :

N_{2} O_{5}, N_{2} O, N O, N_{2} O_{3}

Correct match of acid with its anhydride is

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Pure N2O3 exists only in the solid state at low temperature. Above its melting point, it dissociates to

The correct option is A N2O3⇌N2O+NO2

Pure $N_{2} O_{3}$ exists only in the solid state at low temperature. Above its melting point, it dissociates to

The correct option is A
$N_{2} O_{3} ⇌ N_{2} O + N O_{2}$