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Question

Pure O2 diffuses through an aperture in 224 s, whereas a mixture of O2 and another gas containing 80% O2 diffuses from the same in 234 s under similar conditions of pressure and temperature. What is molecular weight of gas?


A

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B

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C

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D

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Solution

The correct option is D


The gaseous mixture contains 80% O2 and 20% gas.The average molecular weight of mixture is

Mmix=Mixi ----------------------1

As Mmix=Mixiwhere xi=mole fraction.Now for diffusion of gaseous mixture and pure O2

rO2rmix=MmixMO2VO2Vmix×tmixtO2

= Mmix321224×2341=Mmix32 -------------------2

On solving , we get Mmix=34.92gmol1. Thus, substituting in eq(1), we get molecular weight of gas(m)

as M=34.92×10032×8020=46.6gmol1


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