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Standard XII

Chemistry

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Pure O2 dif...

Question

Pure $O_{2}$ diffuses through an aperture in 224 sec, whereas a mixture of $O_{2}$ and another gas containing 80% $O_{2}$ diffuses from the same in 234 sec. What is the molecular weight of the gas?
[as nearest integer]

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Solution

$\frac{t_{2}}{t_{1}} = \sqrt{\frac{M_{m i x}}{M}}$

$\frac{234}{224} = \sqrt{\frac{M_{m i x}}{32}}$

$\Rightarrow M_{m i x} = 34.92 = \frac{100}{\frac{80}{32} + \frac{20}{M}}$
$M = 46.6 \approx 47$

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Similar questions

Q. Pure

O_{2}

diffuses though an aperture in

224

sec, whereas mixture of

O_{2}

and another gas containing

80

O_{2}

takes

234

sec to effuse out same volume. What is molecular weight of the gas?

Q. Pure

O_{2}

diffuses through an aperture in 224 sec, whereas mixture of

O_{2}

and another gas containing
80 %

O_{2}

takes 234 sec to effuse out same volume. What is molecular weight of the gas ?

(Answer should be the closest integer to the molecular weight).

Q. Pure

O_{2}

diffuses through an aperture in

224

second, whereas of

O_{2}

and another gas containing

80

O_{2}

diffuses from the same in

234

second. The molecular mass of gas will be :

Q. Pure

O_{2}

diffuses through an aperture in

224

second, whereas mixture of

O_{2}

and another gas containing

10

O_{2}

diffuses from the same in

336

second. What is the molecular mass of the other gas?

Pure $O_{2}$ diffuses through an aperture in 224 s, whereas a mixture of $O_{2}$ and another gas containing 80% $O_{2}$ diffuses from the same in 234 s under similar conditions of pressure and temperature. What is molecular weight of gas?

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Pure O2 diffuses through an aperture in 224 sec, whereas a mixture of O2 and another gas containing 80% O2 diffuses from the same in 234 sec. What is the molecular weight of the gas?[as nearest integer]

t2t1=√MmixM234224=√Mmix32⇒Mmix=34.92=1008032+20MM=46.6≈47

Pure $O_{2}$ diffuses through an aperture in 224 sec, whereas a mixture of $O_{2}$ and another gas containing 80% $O_{2}$ diffuses from the same in 234 sec. What is the molecular weight of the gas?
[as nearest integer]

$\frac{t_{2}}{t_{1}} = \sqrt{\frac{M_{m i x}}{M}}$

$\frac{234}{224} = \sqrt{\frac{M_{m i x}}{32}}$

$\Rightarrow M_{m i x} = 34.92 = \frac{100}{\frac{80}{32} + \frac{20}{M}}$
$M = 46.6 \approx 47$