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Elevation in Boiling Point

Pure water bo...

Question

Pure water boils at ${99.725}^{o} C$ at shimla. If $K_{b}$ for water is $0.51 K m o l^{- 1} k g$ , the boiling point of $0.69$ molal urea solution will be:

100.35

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100.08

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99.37

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N o n e o f t h e s e

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Solution

The correct option is B $100.08$
$Δ T_{b} = K_{b} \times m$
$= 0.513 \times 0.69$
$= {0.3539}^{0} C$
Boiling point of solution= $= {99.725}^{0} C + {0.3539}^{0} C$
$= {100.079}^{0} C$

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