Put $> or <$ sign in the boxes:
${(285)}^{0} {▭ (- 3)}^{2}$

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Solution

Comparing the exponents :
Given exponential form: ${(285)}^{0}$ and ${(- 3)}^{2}$
As we know the law of exponential is:
${(- x)}^{n} = {(x)}^{n} i f n i s e v e n = - {(x)}^{n} i s n i s o d d$
${(x)}^{0} = 1$
We will solve both exponential forms one by one:
${(285)}^{0} = 1 {U \sin g {(x)}^{0} = 1}$ .
And ${(- 3)}^{2} = 9 {A s 2 i s e v e n}$
Now we can see that $1 < 9$
Hence, ${(285)}^{0} < {(- 3)}^{2}$

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