Question

Put $>or<$ sign in the box:

${(-9)}^4\times 0{\square (-1)}^{49}$

Answer 1

We know that,

$$\begin{gathered} {(-x)}^n={\left(x\right)}^{n}ifniseven \\ =-{\left(x\right)}^{n}isnisodd \end{gathered}$$

Given exponentials are ${(-9)}^4\times 0$ and ${(-1)}^{49}$

${(-9)}^4\times 0=0$.

And, ${(-1)}^{49}=-1\{\because 49isodd\}$

Now, we can see that $0>-1$

Hence, ${(-9)}^4\times 0>{(-1)}^{49}$