Put > or < sign in the boxes:
${(- 8)}^{2} {▭ (- 6)}^{3}$

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Solution

Hint: As we know the law of exponential is:
${(- x)}^{n} = {(x)}^{n} i f n i s e v e n = - {(x)}^{n} i s n i s o d d$
Step 1: Given exponential form: ${(- 8)}^{2}$ and ${(- 6)}^{3}$
We will solve both exponential forms one by one:
${(- 8)}^{2} = 64 {A s 2 i s e v e n}$ .
And ${(- 6)}^{3} = - 216 {A s 3 i s o d d}$
Now we can see that $64 > - 216$
Hence, ${(- 8)}^{2} > {(- 6)}^{3}$ .

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