Put the correct number in the box, so that the equation remains true.
If 10a=55-a then ×10a=8(55-a)
Given, 10a=55-a
⇒10a=55-a
Multiply both sides by 8 we get:
⇒10a×8=55-a×8⇒8×10a=855-a[Byassocoiativeproperty]
By comparing it with ×10a=8(55-a)We get 8 as the number to be filled in the box.
Hence, If 10a=55-a then 8×10a=8(55-a).
If 4x-10=30 then 4x-10+5=30
If 11y-100=y+10 then 11y-100=y+10