Put the $>, < o r =$ signs without changing into equivalent fractions. Apply the rule.
$\frac{4}{7} □ \frac{4}{9}$

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Solution

Both numbers having same numerator but first has less denomerator so it will be more than second number . Hence $\frac{4}{7} > \frac{4}{9}$

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Similar questions

>, < o r =

\frac{8}{19} □ \frac{8}{11}

Compare the fractions and put an appropriate sign:

$\frac{1}{7} □ \frac{1}{4}$

Question 2(b) :

Compare the fractions and put an appropriate sign:

$\frac{1}{7} □ \frac{1}{4}$

\frac{4}{9}

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