Put the $>, < o r =$ signs without changing into equivalent fractions. Apply the rule.
$\frac{5}{12} □ \frac{5}{11}$

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Solution

Both terms have same Numerator but second term has less Denomentor so it will be more than first term . Hence $\frac{5}{12} > \frac{5}{11}$

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Similar questions

>, < o r =

\frac{1}{7} □ \frac{1}{9}

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Question 2(c) :

Compare the fractions and put an appropriate sign:

$\frac{4}{5} □ \frac{5}{5}$

Compare the fractions and put an appropriate sign:

$\frac{3}{5} □ \frac{3}{7}$

Question 2(a) :

Compare the fractions and put an appropriate sign:

$\frac{3}{6} □ \frac{5}{6}$

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