Put the sign $>, <$ or $=$ in the box.
$2^{8} □ 8^{2}$ .

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Solution

We have :
$2^{8} = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 = 256$
$8^{2} = 8 \times 8 = 64$
Since, $256$ is greater than $64$ .
Thus, $2^{8} > 8^{2}$ .

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