PV versus T graph of equal masses of H 2- He and O 2 is shown in figure- Choose the correct alternative-A- A corresponds to H 2- B to He and C to O 2B- A corresponds to He- B to H 2 and C to O 2C- A corresponds to He- B to O 2 and C to H 2D- A corresponds to O 2- B to H 2 and C to He

The correct option is A A corresponds to H_2, B to He and C to O_2pV=μ RT=m/MRT⇒pV/T∝1/M(∵ M=Molecular mass) From graph (pV/T )_A lt;(pV/T )_B lt;(pV/T )_C ...

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Byju's Answer

Standard XII

Mathematics

Special Integrals - 1

pV versus T g...

Question

pV versus T graph of equal masses of $H_{2}$ , He and $O_{2}$ is shown in ﬁgure. Choose the correct alternative.

A corresponds to

H_{2}

, B to He and C to

O_{2}

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A corresponds to He, B to

H_{2}

and C to

O_{2}

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A corresponds to He, B to

O_{2}

and C to

H_{2}

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A corresponds to

O_{2}

, B to

H_{2}

and C to He

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Solution

The correct option is A A corresponds to $H_{2}$ , B to He and C to $O_{2}$
$p V = μ R T = \frac{m}{M} R T \Rightarrow \frac{p V}{T} \propto \frac{1}{M}$ ( $∵$ M=Molecular mass)
From graph ${(\frac{p V}{T})}_{A} < {(\frac{p V}{T})}_{B} < {(\frac{p V}{T})}_{C}$
$\Rightarrow M_{A} > M_{B} > M_{C}$

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pV versus T graph of equal masses of H2, He and O2 is shown in ﬁgure. Choose the correct alternative.

The correct option is A A corresponds to H2, B to He and C to O2pV=μRT=mMRT⇒pVT∝1M(∵ M=Molecular mass) From graph (pVT)A<(pVT)B<(pVT)C ⇒MA>MB>MC

pV versus T graph of equal masses of $H_{2}$ , He and $O_{2}$ is shown in ﬁgure. Choose the correct alternative.

The correct option is A A corresponds to $H_{2}$ , B to He and C to $O_{2}$
$p V = μ R T = \frac{m}{M} R T \Rightarrow \frac{p V}{T} \propto \frac{1}{M}$ ( $∵$ M=Molecular mass)
From graph ${(\frac{p V}{T})}_{A} < {(\frac{p V}{T})}_{B} < {(\frac{p V}{T})}_{C}$
$\Rightarrow M_{A} > M_{B} > M_{C}$