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Question

px2+(4p2−3q)x−12pq=

A
(x4p)(px3q)
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B
(x+4p)(px3q)
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C
(x+4p)(px+3q)
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D
(x4p)(px+3q)
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Solution

The correct option is B (x+4p)(px3q)
We have, px2+(4p23q)x12pq
Also can be written as,
px2+4p2x3qx12pq=px(x+4p)3q(x+4p) (taking (x+p) common)=(px3q)(x+4p)

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