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Question

Pyrite (FeS2), crystallizes in a cubic unit cell with a cell edge of 0.540 nm. The density of pyrite is 5.02 g/cm3. How many Fe2+ and S2−2 ions are present in a single unit cell? (S=32 u, Fe=56 u)

A
1Fe2+ and 1S22
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B
2Fe2+ and 2S22
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C
4Fe2+ and 4S22
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D
6Fe2+ and 6S22
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Solution

The correct option is C 4Fe2+ and 4S22
We know that,
d=ZMa3NA
d - density of the crystal,
Z- Number of unit cell
MM - Molecular mass
a - edge length
NA - Avagadro number

5.02=n(120)6.023×1023(5.4×108)3
n=4, i.e., 4Fe2+ and 4S22

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