Pyruvic acid formed during glycolysis is oxidised to CO $_{2}$ and H $_{2}$ O in

Calvin cycle.

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Hill reaction.

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Krebs cycle.

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Nitrogen cycle.

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Solution

The correct option is C Krebs cycle.
During glycolysis process, glucose is broken down into two molecules of pyruvate and the pyruvate enters into the mitochondria where it is oxidized through the citric acid cycle to carbon dioxide and water.
So the correct option is 'Krebs cycle.'

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{C O}_{2}

H_{2} O

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Glycolysis is the breakdown of glucose to pyruvic acid. How many molecules of pyruvic acid are formed from one molecule of glucose?

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